Optimal. Leaf size=143 \[ -\frac {\sin (c+d x)}{9 d (a+a \cos (c+d x))^5}+\frac {5 \sin (c+d x)}{63 a d (a+a \cos (c+d x))^4}+\frac {\sin (c+d x)}{21 a^2 d (a+a \cos (c+d x))^3}+\frac {2 \sin (c+d x)}{63 a d \left (a^2+a^2 \cos (c+d x)\right )^2}+\frac {2 \sin (c+d x)}{63 d \left (a^5+a^5 \cos (c+d x)\right )} \]
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Rubi [A]
time = 0.07, antiderivative size = 143, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 3, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {2829, 2729,
2727} \begin {gather*} \frac {2 \sin (c+d x)}{63 d \left (a^5 \cos (c+d x)+a^5\right )}+\frac {2 \sin (c+d x)}{63 a d \left (a^2 \cos (c+d x)+a^2\right )^2}+\frac {\sin (c+d x)}{21 a^2 d (a \cos (c+d x)+a)^3}+\frac {5 \sin (c+d x)}{63 a d (a \cos (c+d x)+a)^4}-\frac {\sin (c+d x)}{9 d (a \cos (c+d x)+a)^5} \end {gather*}
Antiderivative was successfully verified.
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Rule 2727
Rule 2729
Rule 2829
Rubi steps
\begin {align*} \int \frac {\cos (c+d x)}{(a+a \cos (c+d x))^5} \, dx &=-\frac {\sin (c+d x)}{9 d (a+a \cos (c+d x))^5}+\frac {5 \int \frac {1}{(a+a \cos (c+d x))^4} \, dx}{9 a}\\ &=-\frac {\sin (c+d x)}{9 d (a+a \cos (c+d x))^5}+\frac {5 \sin (c+d x)}{63 a d (a+a \cos (c+d x))^4}+\frac {5 \int \frac {1}{(a+a \cos (c+d x))^3} \, dx}{21 a^2}\\ &=-\frac {\sin (c+d x)}{9 d (a+a \cos (c+d x))^5}+\frac {5 \sin (c+d x)}{63 a d (a+a \cos (c+d x))^4}+\frac {\sin (c+d x)}{21 a^2 d (a+a \cos (c+d x))^3}+\frac {2 \int \frac {1}{(a+a \cos (c+d x))^2} \, dx}{21 a^3}\\ &=-\frac {\sin (c+d x)}{9 d (a+a \cos (c+d x))^5}+\frac {5 \sin (c+d x)}{63 a d (a+a \cos (c+d x))^4}+\frac {\sin (c+d x)}{21 a^2 d (a+a \cos (c+d x))^3}+\frac {2 \sin (c+d x)}{63 a^3 d (a+a \cos (c+d x))^2}+\frac {2 \int \frac {1}{a+a \cos (c+d x)} \, dx}{63 a^4}\\ &=-\frac {\sin (c+d x)}{9 d (a+a \cos (c+d x))^5}+\frac {5 \sin (c+d x)}{63 a d (a+a \cos (c+d x))^4}+\frac {\sin (c+d x)}{21 a^2 d (a+a \cos (c+d x))^3}+\frac {2 \sin (c+d x)}{63 a^3 d (a+a \cos (c+d x))^2}+\frac {2 \sin (c+d x)}{63 d \left (a^5+a^5 \cos (c+d x)\right )}\\ \end {align*}
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Mathematica [A]
time = 0.20, size = 97, normalized size = 0.68 \begin {gather*} \frac {\sec \left (\frac {c}{2}\right ) \sec ^9\left (\frac {1}{2} (c+d x)\right ) \left (63 \sin \left (\frac {d x}{2}\right )-63 \sin \left (c+\frac {d x}{2}\right )+84 \sin \left (c+\frac {3 d x}{2}\right )+36 \sin \left (2 c+\frac {5 d x}{2}\right )+9 \sin \left (3 c+\frac {7 d x}{2}\right )+\sin \left (4 c+\frac {9 d x}{2}\right )\right )}{8064 a^5 d} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.13, size = 58, normalized size = 0.41
method | result | size |
derivativedivides | \(\frac {-\frac {\left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{9}-\frac {2 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{7}+\frac {2 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3}+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{16 d \,a^{5}}\) | \(58\) |
default | \(\frac {-\frac {\left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{9}-\frac {2 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{7}+\frac {2 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3}+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{16 d \,a^{5}}\) | \(58\) |
risch | \(\frac {4 i \left (63 \,{\mathrm e}^{5 i \left (d x +c \right )}+63 \,{\mathrm e}^{4 i \left (d x +c \right )}+84 \,{\mathrm e}^{3 i \left (d x +c \right )}+36 \,{\mathrm e}^{2 i \left (d x +c \right )}+9 \,{\mathrm e}^{i \left (d x +c \right )}+1\right )}{63 d \,a^{5} \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )^{9}}\) | \(80\) |
norman | \(\frac {\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{16 a d}+\frac {5 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{48 a d}+\frac {\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )}{24 a d}-\frac {\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )}{56 a d}-\frac {25 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{1008 a d}-\frac {\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )}{144 a d}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{4}}\) | \(133\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.30, size = 87, normalized size = 0.61 \begin {gather*} \frac {\frac {63 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {42 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} - \frac {18 \, \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}} - \frac {7 \, \sin \left (d x + c\right )^{9}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{9}}}{1008 \, a^{5} d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.39, size = 123, normalized size = 0.86 \begin {gather*} \frac {{\left (2 \, \cos \left (d x + c\right )^{4} + 10 \, \cos \left (d x + c\right )^{3} + 21 \, \cos \left (d x + c\right )^{2} + 25 \, \cos \left (d x + c\right ) + 5\right )} \sin \left (d x + c\right )}{63 \, {\left (a^{5} d \cos \left (d x + c\right )^{5} + 5 \, a^{5} d \cos \left (d x + c\right )^{4} + 10 \, a^{5} d \cos \left (d x + c\right )^{3} + 10 \, a^{5} d \cos \left (d x + c\right )^{2} + 5 \, a^{5} d \cos \left (d x + c\right ) + a^{5} d\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 3.12, size = 85, normalized size = 0.59 \begin {gather*} \begin {cases} - \frac {\tan ^{9}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{144 a^{5} d} - \frac {\tan ^{7}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{56 a^{5} d} + \frac {\tan ^{3}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{24 a^{5} d} + \frac {\tan {\left (\frac {c}{2} + \frac {d x}{2} \right )}}{16 a^{5} d} & \text {for}\: d \neq 0 \\\frac {x \cos {\left (c \right )}}{\left (a \cos {\left (c \right )} + a\right )^{5}} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.48, size = 59, normalized size = 0.41 \begin {gather*} -\frac {7 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 18 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 42 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 63 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{1008 \, a^{5} d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.40, size = 58, normalized size = 0.41 \begin {gather*} \frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (-7\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8-18\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+42\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+63\right )}{1008\,a^5\,d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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